A stone of mass 2kg whirled in a horizontal circle attached at the end of 1.5 m long string. If the string makes an angle of ` 30 ^@ ` with vertical, compute its period ` ( g = 9.8 m//s ^ 2 ) ` .

A stone of mass 2kg whirled in a horizontal circle attached at the end

1.	A stone of mass 2kg whirled in a horizontal circle attached at the end of 1.5 m long string. If the string makes an angle of ` 30 ^@ ` with vertical, compute its period ` ( g = 9.8 m//s ^ 2 ) ` .
Answer» Given : Length of string (l) = 1.5 m, ` theta = 30 ^@, g = 9.8 m//s ^ 2 ` Mass of stone (m) = 2kg Period (T) ` = 2pi sqrt ( ( lcos theta ) /( g ) ) ` ` = 2 xx 3.142 sqrt ( ( 1.5 xx 1.732 ) /( 2xx 9.8 ) ) ` ` = 2 xx 3.142 sqrt ( 0.1325 ) ` ` = 2 xx 3.142 xx 0.3641 ` ` = 2.2874 ` s

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A stone of mass 2kg whirled in a horizontal circle attached at the end of 1.5 m long string. If the string makes an angle of ` 30 ^@ ` with vertical, compute its period ` ( g = 9.8 m//s ^ 2 ) ` .

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