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What is Broglie wavelength of an electron accelerated through 25000 volt ? |
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Answer» Given ` : V = 25000 ` volt. We have, de - Broglie wavelength ` lamda = ( 12.27 ) /( sqrt V) Å ` ` lamda = ( 12.27 ) /( sqrt ( 25000) ) ` ` lamda = 0.07766 Å ` |
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