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What is Broglie wavelength of an electron accelerated through 25000 volt ?

Answer» Given ` : V = 25000 ` volt.
We have, de - Broglie wavelength
` lamda = ( 12.27 ) /( sqrt V) Å `
` lamda = ( 12.27 ) /( sqrt ( 25000) ) `
` lamda = 0.07766 Å `


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