InterviewSolution
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InterviewSolution
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A stone of of mass 0 .25 kg tied to the end of a string is whirled round in a circle of radius 1.5 m with a speed of `40 rev//min` in a horizontal plane What is the tension in the string ? What is the maximum speed with which the stone can be whirled around If the string can withstand a maximum tension of 200 N ? |
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Answer» Here `m = 0.25 kg , r = 1.5 m,n = 40 rpm = (40)/(60) "rps" = (2)/(3) rps , T = ?` `T = m t omega^(2) = m r (2 pi n )^(2) = 4 pi^(2) m r n^(2)` `T = 4 xx (22)/(7) xx (22)/(7) xx 0.25 xx 1.5 xx ((2)/(3))^(2) = 6.6 N` If `T_(max) = 200 N` then from `T_(max) = (m upsilon^(2)max)/(r)` `upsilon^(2)-_(max) = (T_(max) xx r)/(m) = (200 xx 1.5)/(0.25) = 1200` `upsilon_(max) = sqrt1200 = 34 .6 m//s`. |
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