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A stone projected vertically up from the ground reaches a height `y` in its path at `t_(1)` seconds and after further `t_(2)` seconds reaches the ground. The height y is equal toA. `(1)/(2)g(t_(1)+t_(2))`B. `(1)/(2)g(t_(1)+t_(2))^(2)`C. `(1)/(2)g t_(1)t_(2)`D. `g t_(1)t_(2)` |
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Answer» Correct Answer - C `h=y=(1)/(2)g t_(1)t_(2)` |
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