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A stone thrown vertically upward with initial velocity u reaches a height h before coming down . show that the time taken to go up is same as the time taken to come down answer the following |
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Answer» Explanation: Let us consider an object which is projected vertically upwards with initial velocity u which reaches a maximum height h. Acceleration due to gravity=-g Equation of Motion for a body projected thrown upwards : V=u-gt----------(1) h=ut-1/2gt² -----------(2) v²-u²=-2gh --------(3) Equations of motion for freely falling body : for free fall : Initial velocity=u=0 g=g V=gt----------(4) h=1/2gt²-------(5) v²=2gh------(6) Time of Ascent is the time taken by body thrown up to reach maximum height h At maximum height , V=0 Equation (1) turns to u=gt1 t1=u/g ----------(7) Maximm height h=u²/2g ----------(8) Time of descent : After reaching maximum height , the body begins to travel downward LIKE free fall so equation (5) h=1/2gt₂² t₂²=2h/g t₂=√2h/g but from equation (9) t₂=√2xu²/2g² t₂=u/g -----------------equation (10) ∴t₁=t₂ The time ascent is equal to time of descent in CASE of BODIES moving under gravity. |
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