1.

A straight wire carries a current of 3 A.Calculate the magnitude of the magnetic field at apoint 15 cm away from the wire.

Answer»

B= (µₒI)/2πa

here, I = 3 A and a = 15 cm = 15 * 10^-2 m and the value of µₒ is 4π * 10 ^-7

so, B = [4π*(10)^-7 (3)] / [2π(15*(10)^-2)]cancelling 4π by 2π, we get,B = [2*(10)^-7*(3)] / [15*(10)^-2]B = [6*(10)^-7] / [1.5*(10)^-1]B = 4*10^-6T



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