A stream of water flowing horizontal with a speed of `15 ms^(-1)` gushes out of tube of cross sectional area `10^(2) m^(2)` and hits at a vertical wall nearby . What is the force exerted by the impact of water, assuming that water rebounds with the same speed.

A stream of water flowing horizontal with a speed of `15 ms^(-1)` gush

1.	A stream of water flowing horizontal with a speed of `15 ms^(-1)` gushes out of tube of cross sectional area `10^(2) m^(2)` and hits at a vertical wall nearby . What is the force exerted by the impact of water, assuming that water rebounds with the same speed.
Answer» Correct Answer - `4500N` . Here, `upsilon =15m//s, A = 10^(-2) m^(2)` Volume of water gushing out//sec `=A xx upsilon = 10^(-2) xx 15m^(3)//s` Mass of water flowing out/sec = Volume `xx` density `m = 15 xx 10^(-2) xx 10^(3) = 150kg//s` As water rebounds with the same speed, therefore Impact of water = force on the wall = change in linear momentum/sec =mass/sec `xx` change in velocity `=150 xx (15 + 15) = 4500N`.

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A stream of water flowing horizontal with a speed of `15 ms^(-1)` gushes out of tube of cross sectional area `10^(2) m^(2)` and hits at a vertical wall nearby . What is the force exerted by the impact of water, assuming that water rebounds with the same speed.

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