A string is stretched between fixed points separated by `75.0cm`. It is observed to have resonant frequencies of `420 Hz` and `315 Hz`. There are no other resonant frequencies between these two. Then, the lowest resonant frequency for this string isA. `105 Hz`B. `155 Hz`C. `205 hz`D. `10.5 hz`

A string is stretched between fixed points separated by `75.0cm`. It i

1.	A string is stretched between fixed points separated by `75.0cm`. It is observed to have resonant frequencies of `420 Hz` and `315 Hz`. There are no other resonant frequencies between these two. Then, the lowest resonant frequency for this string isA. `105 Hz`B. `155 Hz`C. `205 hz`D. `10.5 hz`
Answer» Correct Answer - A Two consecutive resonant frequencies for a string fixed at both ends will be `(nv)/(2l)` and `((n+1)v)/(2l)` `implies((n+1)v)/(2l)-(nv)/(2l)=420-315` `implies(v)/(2l)=105Hz`. Which is the minimum resonant frequency.

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A string is stretched between fixed points separated by `75.0cm`. It is observed to have resonant frequencies of `420 Hz` and `315 Hz`. There are no other resonant frequencies between these two. Then, the lowest resonant frequency for this string isA. `105 Hz`B. `155 Hz`C. `205 hz`D. `10.5 hz`

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