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A string of length 1 m is fixed at one end and car-ries a mass 100 g at other end. The string makes2revolutions per second around a vertical axispassing through its second end. Find the tension inthe string. |
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Answer» w = 2pi*2/pi = 4 rad/s. npw consider angle thethaa wth vertical and do comonents of Tension along horizontal and vertial and balnce them with mg and mw^2r where from geomtery r = lsinthetha. after balancing the eqns would be: T = mw^2l T = 100/1000 * 16 * 1 = 1.6 N in vertical direcn. Tcosthetha = mg cosththa = 5/18 or thetha = arccos(5/18) |
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