1.

A string of length 1 m is fixed at one end and car-ries a mass 100 g at other end. The string makes2revolutions per second around a vertical axispassing through its second end. Find the tension inthe string.

Answer»

w = 2pi*2/pi = 4 rad/s.

npw consider angle thethaa wth vertical and do comonents of Tension along horizontal and vertial and balnce them with mg and mw^2r

where from geomtery r = lsinthetha.

after balancing the eqns would be:

T = mw^2l

T = 100/1000 * 16 * 1 = 1.6 N

in vertical direcn.

Tcosthetha = mg

cosththa = 5/18

or

thetha = arccos(5/18)



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