1.

A string vibrates with a frequency of 250Hz. If the distance between two consecutive troughs of a transverse wave produced in the string is 10cm, find the velocity and time period of the wave.

Answer»

ANSWER:

given wavelength is 10 cm

time period 1/ f= 4× 10 RAISED minus 4

speed is f lamda= 10×250= 2500 cm per SEC



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