A student is standing at a distance of 50metres from the bus. As soon

1.	A student is standing at a distance of 50metres from the bus. As soon as the bus starts its motion with anacceleration of lms. the s student starts running towards the bus with a uniform velocity n. Assuming themotion to be along a straight road, the minimum value of u, so that the students is able to catch the bus is
Answer» Answer: u min = 10 m/s Acceleration of bus a = 1 m/s In 10 seconds, the distance travelled by te bus S can be given as S = ut + 1/2 at² as initial VELOCITY of bus is zero, S = 0 + 0.5×1×10² ∴S = 50 m ....(1) Student in behind the bus by 50 m As calculated above, bus travels distance = 50 m. Thus, the students must TRAVEL min distance = 50 + 50 = 100 m UNIFORM velocity of student can be calculated as U = Distance traveleed ÷ time taken ∴ U = 100 ÷ 10 ∴ U = 10 m/s Minimum value of u, (uniform velocity by the student) so that the student is able to catch the bus = 10 m/s Read more on Brainly.in - brainly.in/question/9351964#readmore Explanation:

A student is standing at a distance of 50metres from the bus. As soon as the bus starts its motion with anacceleration of lms. the s student starts running towards the bus with a uniform velocity n. Assuming themotion to be along a straight road, the minimum value of u, so that the students is able to catch the bus is

Answer»

Answer:

u min = 10 m/s

Acceleration of bus a = 1 m/s

In 10 seconds, the distance travelled by te bus S can be given as

S = ut + 1/2 at²

as initial VELOCITY of bus is zero,

S = 0 + 0.5×1×10²

∴S = 50 m ....(1)

Student in behind the bus by 50 m

As calculated above, bus travels distance = 50 m.

Thus, the students must TRAVEL min distance = 50 + 50 = 100 m

UNIFORM velocity of student can be calculated as

U = Distance traveleed ÷ time taken

∴ U = 100 ÷ 10

∴ U = 10 m/s

Minimum value of u, (uniform velocity by the student) so that the student is able to catch the bus = 10 m/s