1.

A student measured the diameter of a smallsteel ball using a screw gauge of least count0.001 cm. The main scale reading is 5 mm andzero of circular scale division coincides with25 divisions above the reference level. If screwgauge has a zero error of -0.004 cm, the correctdiameter of the ball is(a) 0.521 cm(c) 0.053 cm(b) 0.525 cm(d) 0.529 cm(NEET 2018)

Answer»

Reading of screw gauge= MSR + VSR × LC + zero error= 0.5cm + 25 × 0.001cm + 0.004cm= 0.529cm



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