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A student measures the time period of `100` ocillations of a simple pendulum four times. The data set is `90 s`, 91 s, 95 s, and 92 s`. If the minimum division in the measuring clock is `1 s`, then the reported men time should be:A. `92 pm 3s`B. `92 pm 2s`C. `92 pm 5.0 s`D. `92 pm 1.8 s` |
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Answer» Correct Answer - B `T_(AV)=92s` `(|DeltaT|)_("mean")=1.5s` since uncertainity is 1.5 s so digit 2 in 92 uncertain so reported mean time should be `92 pm 2` |
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