A student performs an experiment for determination of ` g [ = ( 4 pi^(2) L)/(T^(2)) ] , L ~~ 1m` , and he commits an error of `Delta L`. For `T` he takes the time of `n` oscillations with the stop watch of least count ` Delta T` . For which of the following data , the measurement of `g` will be most accurate ?A. `Delta L = 0.5, Delta T - 0.1, n = 20`B. `Delta L = 0.5, Delta T = 0.1,n = 50`C. `DeltaL = 0.5, Delta T = 0.01, n = 20`D. `Delta L= 0.1, Delta T = 0.05, n = 50`

A student performs an experiment for determination of ` g [ = ( 4 pi^(

1.	A student performs an experiment for determination of ` g [ = ( 4 pi^(2) L)/(T^(2)) ] , L ~~ 1m` , and he commits an error of `Delta L`. For `T` he takes the time of `n` oscillations with the stop watch of least count ` Delta T` . For which of the following data , the measurement of `g` will be most accurate ?A. `Delta L = 0.5, Delta T - 0.1, n = 20`B. `Delta L = 0.5, Delta T = 0.1,n = 50`C. `DeltaL = 0.5, Delta T = 0.01, n = 20`D. `Delta L= 0.1, Delta T = 0.05, n = 50`
Answer» Correct Answer - D `g=(4pi^(2)l)/(T^(2))rArr(Deltag)/(g)=(Deltal)/(l)+(2 DeltaT)/(T)`Here `T = 2sec` For (A) `(Deltag)/(g)=(0.1)/(1)+(0.2(0.1))/(2) = 0.6` For (B) `(Deltag)/(g)=0.5+(0.2)/(2)=0.6` For (C) `(Deltag)/(g)=0.5+(0.02)/(2)=0.51` For (D) `(Deltag")/(g)=0.1+(0.1)/(2)=0.15` `rArr(Deltag)/(g)` minimum for (D). Also number of observations are maximum in (D)

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