1.

A student need 3.011 xx 10^(23) atoms of each magnesium and carbon. Then how much will he take both the elements by weight?

Answer»

24 g Mg and 6g C
12 g C and 24 g Mg
20 g Mg and 10g C
12 g Mg and 6 g C

Solution :Mole of 12G Mg = `(12)/(24)` = 0.5
Mole of 6 g C=`(6)/(12)` =0.5


Discussion

No Comment Found