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A substance undergoes first order decomposition. The decomposition follows two parallel first order reaction as: and `KP_(1)=1.26xx10^(-4)sec^(-1)` `K_(2)=3.80xx10^(-5)sec^(-1)` The percentage distribution of B and C are:A. `80%B and 20%C`B. `76.83% and 231.7%C`C. `90%B and 10%C`D. `60%B and 40%C` |
Answer» Correct Answer - b For parallel path reaction, `K_("average")=K_(1)+K_(2)` `=1.26xx10^(-4)+3.8xx10^(-5)` `1.64xx10^(-4) sec^(-1)` Also fractional yield of `B=K_(B)/K_(av)` `=(1.26xx10^(-4))/(1.64xx10^(-4))=0.7683` Fraction yield of `A=K_(A)/K_(av)` `=(3.8xx10^(-5))/(1.64xx10^(-4))=0.2317` |
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