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A subtance undergoes first order decomposition involving two parallel first order reaction as `:` The mole percent of B in the products is `:`A. 23.17B. 76.68C. 30.16D. 69.84 |
Answer» Correct Answer - 2 `(k_(1)xx100)/(k_(1)+k_(2))=(1.28xx10^(-4))/(1.25xx10^(-4)+3.80xx10^(-5))=76.83` |
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