InterviewSolution
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InterviewSolution
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A swimmer crosses a flowing stream of width `omega` to and fro in time `t_(1)`. The time taken to cover the same distance up and down the stream is `t_(2)`. If `t_(3)` is the time the swimmer would take to swim a distance `2omega` in still water, thenA. `T_(1) = T_(2).T_(3)`B. `T_(1)^(2) = T_(2).T_(3)`C. `T_(2)^(2) = T_(1).T_(3)`D. `T_(2)^(3) = T_(1).T_(2)` |
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Answer» Correct Answer - B Let `v` and `u` be speeds of swimmer and river respectively. `T_(1) = (2b)/(sqrt(v^(2) - u^(2))) , T_(2) = (b)/(v - u) + (b)/(v + u) = (2bv)/(v^(2) - u^(2)) , T_(3) = (2b)/(v)` `:. T_(1)^(2) = t_(2) . T_(3)` |
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