1.

(A) T/8(B) T/12(C) T/2Two simple harmonic motion of angular frequency 100 and 1000 radThe ratio of their maximum acceleration iss- have the same displacement amplitudeAIPMT Prelims 2008(D) 1: 102(A) 1: 103(B) 1: 104Owith an amplitude a and time period T. The

Answer»

Acceleration of simple harmonic motion is

amax = - w^2 A

amax1/amax2 = w1^2/w2^2

amax1/amax2 = (100)^2/(1000)^2

amax1/amax2 = 1/10^2

(D) is correct option



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