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A telescope has an objective of focal length `50cm` and an eyepiece of focal length `5cm.` The least distance of distinct vision is `25cm.` The telescope is focused for distinct vision on a scale `2m` away from the objective. Calculate (a) magnification produced and (b) separation between objective and eyepiece. |
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Answer» Correct Answer - B::C Given, `f_0=50cm` and `f_e=5cm` For objective `1/v-1/-200=1/50` `:. v_0=200/3cm` `m_0=v_0/u_0=((200//3))/(-200)=-(1)/(3)` For eyepiece `1/-25-1/u_e=1/5` `:. u_e=-25/6cm` and `m_e=v_e/u_e=(-25)/-(25//6)=6` (a) Magnification, `m=m_0xxm_e=-2` (b) Separation between objective and eyepiece, `L=v_0+|u_e|=200/3+25/6=425/6` `=70.83cm` |
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