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a thermodynamic process is carried out from an original state D to an intermediate state E by the linear process shown in figure. The total work is done bvy the gas from D to E to F is A. 100 JB. 800 JC. 300 JD. 250 J |
Answer» Correct Answer - B Total work done by the gas from D to E to F is equal to the area of `DeltaDEF` `therefore` The area of `Delta DEF=(1)/(2)DFxxEF` Here DF change in pressure =600-200=400 N `m^(-2)` Also EF=change in volume = `7m^(3)-3m^(3)=4m^(3)` Area of `DeltaDEF =(1)/(2)xx400xx4=800J` Thus the total work done by the gas from D to E to F is 800 J. |
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