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A thermodynamic process of one mole ideal monoatomic gas is shown in figure. The efficiency of cyclic process `ABCA` will beA. 0.25B. 0.125C. 0.5D. 0.077 |
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Answer» Correct Answer - D `W=(1)/(2)P_(0)V_(0), T_(A)=T_(0),T_(B)=2T_(0),T_(C)=4T_(0)` Heat supplied =`Q_(AB)+Q_(BC)=C_(V)T_(0)+C_(p)2T_(0)` `=(13)/(2)RT_(0)=(13)/(2)P_(0)V_(0)` `therefore` Efficiency of the cyclic process `((1)/(2) P_(0)V_(0))/((13)/(2)P_(0)V_(0))xx100=(1)/(13)xx100=7.7%` |
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