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A Thief Steals A Car At 2.30 P.m And Drives It At 60 Kmph. The Theft Is Discovered At 3 P.m And The Owner Sets Off In Another Car At 75 Kmph. When Will Be Overtake The Thief |
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Answer» As THEFT is discovered at 3:00pm but Thief STOLE the car at 2:30. This means thief COVERED some DISTANCE in this 30 min gap. Distance travelled by thief in 30 min = 60 * 1/2 = 30 km Owner Discovered Car at 3:00pm Now relative speed = (75-60)km/hr = 15km/hr Time needed to travel 30km by the speed of 15km/hr. Time at which owner MEETS thief = 30/15 = 2 hrs So After 2 hrs (i.e,at 5:00 pm) the owner will catch/overtake the thief As Theft is discovered at 3:00pm but Thief stole the car at 2:30. This means thief covered some distance in this 30 min gap. Distance travelled by thief in 30 min = 60 * 1/2 = 30 km Owner Discovered Car at 3:00pm Now relative speed = (75-60)km/hr = 15km/hr Time needed to travel 30km by the speed of 15km/hr. Time at which owner meets thief = 30/15 = 2 hrs So After 2 hrs (i.e,at 5:00 pm) the owner will catch/overtake the thief |
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