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A thin equi-convex lens is made of glass of refractive index `1.5` and its length is `0.2 m.` If it acts as a concave lens of `0.5 m` focal length when dipped in a liquid, the refractive index of the liquid isA. `17/8`B. `15/8`C. `13/8`D. `9/8` |
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Answer» Correct Answer - B `1/0.2=(1.5-1)(1/R_1-1/R_2)…….(i)` `1/-0.5=(1.5/mu-1)(1/R_1-1/R_2)…..(ii)` Here, `mu=`refractive index of medium or liquid. Dividing Eq.(i) by Eq.(ii), we get `-5=1/((1.5//mu)-1) or mu=15/8` |
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