1.

A thin rod of uniform density has length 0.1m and mass 120gm . Find its M.I. adout the transverse axis passing through its centre of mass

Answer»

The moment of INERTIA about the transverse axis = 0.000025 Kg m²

Length of the rod = L = 0.1 m

MASS of the rod = 120 gm = m = 0.12 Kg

The CENTER of mass of the uniform density rod will be the midpoint of the rod .

The moment of inertia about the transverse axis passing through its centre of mass = M(l/2)² / 12

= 0.12 × (0.05)²/12

= 0.000025 Kg m²



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