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A thin uniform rod of length `l` and mass `m` is swinging freely about a horizontal axis passing through its end. Its maximum angular speed is `omega`. Its centre of mass rises to a maximum height of -

Answer» `mgh=1/2 Iomega^(2)=1/2(ml^(2))/3 omega^(2)rArrh=(l^(2)omega^(2))/(6g)`


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