1.

A torch bulb is rated 25 V and 750 mA. Cali ulate () its power (i) its resistance (ii) theenergy consumed, if the bulb is lighted for jour hoursList three properties of magnetic field lin

Answer»

V=2.5 VI=750mA= 750x10⁻³Apower =p=?Power =V*I =2.5x750x10⁻³=1.875Wreistance :V=IRR=V/I=2.5/750x10⁻³=3.3 ohmsEnergy consumed if bulb is lighted for 4 hours :E=p*t=1.875x4=7.500Wh=27x 10³joules



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