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A train accelarates at 34km/h to 54km/h in 10sec. Find its accelaration |
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Answer» Answer: Initial speed u = 36 km/h = 36 X 1000/3600 m/s = 10 m/s FINAL speed v = 54 km/h = 54 x 1000/3600 m/s = 15 m/s TIME t = 10 s Acceleration a = (v - u)/t = (15 - 10)/10 = 5/10 = 0.5 m/s2. Distance travelled S = ut + ½ at2 = 10 x 10 + ½ x 0.5 x 10 x 10 m = 100 + 25 = 125 m |
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