A train accelerates uniformly from 36 kmh -1 to 72 kmh -1 in 10 sec .find the distance

A train accelerates uniformly from 36 kmh -1 to 72 kmh -1 in 10 sec .f

1.	A train accelerates uniformly from 36 kmh -1 to 72 kmh -1 in 10 sec .find the distance
Answer» Distance covered = 150 mExplanation:Initial velocity U = 36 km/h = 36 X 5/18 = 10 m/sFinal velocity v = 72 km/h = 72 x 5/18 = 20 m/sacceleration a = (v-u)/t = (20-10)/ 10 = 1 m/s²Distance covered s = ut + 1/2 at² = 10x 10 + 1/2 x 1 x 100 = 100 + 50 = 150m

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A train accelerates uniformly from 36 kmh -1 to 72 kmh -1 in 10 sec .find the distance

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