1.

A train accelerates uniformly from 36km/h to 72km/h in 10s. Find the distance travelled

Answer»

ANSWER:

Given:

Initial velocity = 36 km/hr

Final Velocity = 72 km/hr

Time TAKEN = 10 seconds

To find:

Distance travelled.

Conversion :

Convert unit of velocity from km/hr to

m/s.

1. 36 km/hr = 36 × 5/18 = 10 m/s

2. 72 km/hr = 72 × 5/18 = 20 m/s

Calculation:

Acceleration be denoted as "a"

\therefore \: a = \dfrac{v - u}{t}

= > a = \dfrac{20 - 10}{10}

= > a = 1 \: m {s}^{ - 2}

Now distance travelled :

\therefore \: s = ut + \frac{1}{2} a {t}^{2} \\ = > s =( 10 \times 10) + ( \dfrac{1}{2} \times 1 \times {10}^{2} ) \\ = > s = 100 + 50 \\ = > s = 150 \: metres

So final answer :

\boxed{ \red{distance = 150 \: metres}}

Additional information on velocity:

1. It is a VECTOR quantity.

2. It has both directions and magnitude.

3. It is also called the RATE of CHANGE of Displacement.


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