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A Train Covers A Distance In 50 Min ,if It Runs At A Speed Of 48 Kmph On An Average.the Speed At Which The Train Must Run To Reduce The Time Of Journey To 40 Min Will Be? |
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Answer» Time=50/60 hr=5/6hr SPEED=48mph distance=S*T=48*5/6=40km time=40/60hr=2/3hr NEW speed = 40* 3/2 KMPH= 60KMPH. Time=50/60 hr=5/6hr Speed=48mph distance=S*T=48*5/6=40km time=40/60hr=2/3hr New speed = 40* 3/2 kmph= 60kmph. |
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