Saved Bookmarks
| 1. |
A Train Covers A Distance In 50 Minutes, If It Runs At A Speed Of 48kmph On An Average. Find The Speed At Which The Train Must Run To Reduce The Time Of Journey To 40 Minutes? |
|
Answer» We are having time and speed GIVEN, so FIRST we will calculate the distance. Then we can GET new speed for given time and distance. Lets solve it. Time = 50/60 hr = 5/6 hr Speed = 48 mph Distance = S*T = 48 * 5/6 = 40 KM New time will be 40 minutes so, Time = 40/60 hr = 2/3 hr Now we know, Speed = Distance/Time New speed = 40*3/2 kmph = 60kmph. We are having time and speed given, so first we will calculate the distance. Then we can get new speed for given time and distance. Lets solve it. Time = 50/60 hr = 5/6 hr Speed = 48 mph Distance = S*T = 48 * 5/6 = 40 km New time will be 40 minutes so, Time = 40/60 hr = 2/3 hr Now we know, Speed = Distance/Time New speed = 40*3/2 kmph = 60kmph. |
|