1.

A train is moving on a track at `30ms^-1`. A ball is thrown from it perpendicular to the direction of motion with `30 ms^-1` at `45^@` from horizontal. Find the distance of ball from the point of projection on train to the point where it strikes the ground.A. 90 mB. `90(sqrt3)` mC. 60 mD. `60 (sqrt3)`m

Answer» Correct Answer - A
Velocity of train in the direction of train is also `30 m//s`. So there is no relative motion in this
direction. In perpendicular direction,
`d = R = (u^2sin2theta)/g`
`=((30)^2sin90^@)/10 = 90m`.


Discussion

No Comment Found

Related InterviewSolutions