A train starting from a railway station and moving with uniform accele

1.	A train starting from a railway station and moving with uniform acceleration attains a speed 40 km/hr in 10 minutes. Find its acceleration....CAN ANYONE GIVE ME ITS ANSWER STEP BY STEP??????
Answer» Answer: 0.0185m/s² Explanation: Given : INITIAL velocity,u => 0m/s [As it is STARTING from the rest] Final velocity,v => 40km/hr = 11.1m/s [1km/hr = 1000/3600m/s] Time,t = 10min = 1060 = 600s [1min = 60s] Find* : Acceleration,a Solution : According to the 1st equation of motion:- $\sf{}v=u+at$ Put their values and solve it $\implies \sf{} 11.1=0+(a)(600)$ $\implies \sf{} 11.1=600a$ $\implies \sf{} \dfrac{11.1}{600}=a$ $\therefore \sf{} a= 0.0185m/s^2$ Hence,acceleration is equal to 0.0185m/s² ☆Additional Information☆ 2nd equation of motion $\sf{}s=ut + \dfrac{1}{2}at^2$ 3RD equation of motion $\sf{}v^2-u^2=2as$