A train starting from rest attains a velocity of 72 km h -1 in 5 minut

1.	A train starting from rest attains a velocity of 72 km h -1 in 5 minutes.assuming that the accelertaion is uniform .find the distance travelled by the train for attaining this velocity.
Answer» EXPLANATION: first we NEED to find the acceleration= v-u/t=a 72kmh-1= 20ms-1 so, a=20ms-1-0ms-1/5m a= 4m/s^2 now second LAW S=ut+1/2at^2 S=0×5+1/2×4×(5)^2 S=2×(5)^2 S=2×25 S=50m So, THEREFORE the distance is 50m HOPE IT HELPS MATE......

A train starting from rest attains a velocity of 72 km h -1 in 5 minutes.assuming that the accelertaion is uniform .find the distance travelled by the train for attaining this velocity.

Answer»

EXPLANATION:

first we NEED to find the acceleration=

v-u/t=a

72kmh-1= 20ms-1

so, a=20ms-1-0ms-1/5m

a= 4m/s^2

now second LAW S=ut+1/2at^2

S=0×5+1/2×4×(5)^2

S=2×(5)^2

S=2×25

S=50m

So, THEREFORE the distance is 50m

HOPE IT HELPS MATE......

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A train starting from rest attains a velocity of 72 km h -1 in 5 minutes.assuming that the accelertaion is uniform .find the distance travelled by the train for attaining this velocity.

first we NEED to find the acceleration=

v-u/t=a

72kmh-1= 20ms-1

so, a=20ms-1-0ms-1/5m

a= 4m/s^2

now second LAW S=ut+1/2at^2

S=0×5+1/2×4×(5)^2

S=2×(5)^2

S=2×25

S=50m

So, THEREFORE the distance is 50m

HOPE IT HELPS MATE......

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