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A transformer has an efficiency of 60% and works at 5kW. If the secondary voltage is 150 V, then what is the secondary current?(a) 10 A(b) 20 A(c) 30 A(d) 40 AI have been asked this question in an international level competition.This intriguing question comes from Alternating Current in section Alternating Current of Physics – Class 12

Answer»

The correct choice is (b) 20 A

For explanation I would say: Given: efficiency (η) = 60%; Input power (PI) = 5 kW = 5000 W; VS = 150 V

Efficiency (η)=\(\frac {OUTPUT \, power (P_o)}{Input \, power (P_i)}=\frac {V_s I_s}{V_p I_p}\)

\(\frac {60}{100}=\frac {P_o}{5000}\)

Po=\(\frac {60 \TIMES 5000}{100}\)=3000 W

Thus,

Is=\(\frac {P_o}{V_s} = \frac {3000}{150}\)=20 A

Therefore, the current in the secondary coil is 20 A.



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