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What is the power factor for a series LCR circuit at resonance?(a) Infinity(b) -1(c) 0(d) 1I got this question in an interview for job.My question comes from Power in AC Circuit : The Power Factor topic in section Alternating Current of Physics – Class 12

Answer»

The correct option is (d) 1

Explanation: The IMPEDANCE for a series LCR circuit is given as:

Z=\(\sqrt {R^2+(X_L-X_C)^2}\)andcos⁡Φ=\(\frac {R}{Z}\)

At resonance, XL=XC ➔Z = R;

So, the total impedance of the circuit is only due to resistor. The phase ANGLE between voltage and current is zero. THEREFORE,

Φ=0 ➔ POWER factor (cosΦ)=1



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