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A transistor connected in common emitter mode, the voltage drop across the collector is 2 V and `beta` is 50, the base current if `R_C` is `2 kOmega` isA. `40 muA`B. `20 muA`C. `30 muA`D. `15 muA` |
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Answer» Correct Answer - B Using, `I_C=(V_(CE))/R_C=2/(2xx10^3)=10^(-3)`=1 mA `therefore beta=I_C/I_B,I_B=I_C/beta=10^(-3)/50A=20 muA` |
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