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In an n-p-n transistor `10^(10)` electrons enter the emitter in `10^(-6)`s. If 2% of the electrons are lost in the base, find the current transfer ratio and the current amplification factor.A. 0.02B. 7C. 33D. 4.9 |
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Answer» Correct Answer - A As, `I_E=(n_Exxe)/t` and `I_C=(n_Cxxe)/t=((98//100)n_Exxe)/t=98/100xxI_E` Current transfer ratio, `alpha=I_C/I_E=98/100=0.98` Current amplification factor, `beta=alpha/(1-alpha)=0.98/(1-0.98)=49 " " therefore " " alpha/beta=0.98/49=0.02` |
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