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If `alpha and beta` are the current gain in the CB and CE configurations respectively of the transistor circuit, then `(beta-alpha)/(alphabeta)=`A. zeroB. 1C. 2D. 5 |
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Answer» Correct Answer - B Since `beta=alpha/(1-alpha)`...(i) `therefore alphabeta=alpha^2/(1-alpha)-alpha"or" beta-alpha=alpha^2/(1-alpha)`..(ii) `therefore (beta-alpha)/(alphabeta)=(alpha^2/(1-alpha))((1-alpha)/alpha^2)=1` |
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