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A transistor has an `alpha = 0.95` It has change in emitter current of 100 mili-ampere, then the change in collector current is :-A. 95 mAB. 99.05 mAC. 0.95 mAD. 100 mA

Answer» Correct Answer - A
`alpha=(DeltaI_(C))/(DeltaI_(E))rArr DeltaI_(C)=alpha DeltaI_(E)=0.95xx100 mA=95mA`


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