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A transistor has an IE of 0.9mA and amplification factor of 0.98. What will be the IC?(a) 0.745mA(b) 0.564mA(c) 0.236mA(d) 0.882mAThe question was asked in an interview for internship.My question is from The Common Base Configuration topic in section Transistor Characteristics of Electronic Devices & Circuits

Answer» RIGHT ANSWER is (d) 0.882mA

For explanation I would say: GIVEN, IE = 0.9mA, α=0.98

We know, α= IC/IE

So, IC=0.98*0.9=0.882mA.


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