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The base emitter voltage in a cut off region is_________(a) greater than 0.7V(b) equal to 0.7V(c) less than 0.7V(d) cannot be predictedI got this question in unit test.This question is from Transistor as a Switch in chapter Transistor Characteristics of Electronic Devices & Circuits

Answer»

Right answer is (c) less than 0.7V

For explanation: From the CUT off CHARACTERISTICS, the base emitter voltage (VBE) in a cut off REGION is less than 0.7V. The cut off region can be considered as ‘off mode’. Here, VBE > 0.7 and IC=0. For a PNP transistor, the emitter POTENTIAL must be negative with respect to the base.



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