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A transistor is operated in common emitter configuration at `V_(c)=2 V` such that a change in the base current from `100 muA` to `300 muA` produces a change in the collector current from `10 mA` to `20 mA`. The current gain isA. 50B. 75C. 100D. 25 |
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Answer» Correct Answer - A `beta=(DeltaI_(B))/(DeltaI_(B))=(10mA)/(200muA)=(10xx10^(3))/(200)=50` |
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