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A transparent solid cylindrical rod has a refractive index of 2 / root of ( 3) . It is surrounded by air. A light ray is incident at the mid-point of one end of the rod as shown in the figure. The incident angle θ for which the light ray grazes along the wall of the rod is - ( figure of this question is given below ) options : 1) sin ^ -1 (1/2) 2)sin ^-1 ( root of (3) /2 ) 3) sin ^-1 ( 2 / root (3) ) 4) sin ^-1 (1 / root of (3) ) solution is also needed Dont spam from google spam or improper ans will be reported at the spot |
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Answer» ANSWER : I×sin90=32sin(90−α) ⇒cosα=23 So, sinα=1−43 =21 Now, 1×sinθ=3 2sinα=3 2×21=3 1 ⇒θ=sin−13 1 Explanation: |
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