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A transverse traveling wave is given by y = 3 sin(36t + 0.018x + Ď/4), where the distances are in centimetre andtime is in second. Find (i) the speed and direction of propagation (il) the amplitude (ii) the frequency (iv) thedistance between consecutive crests(Ans. 2000 cm/s towards -x-axis, 3 cm, 5.729 Hz, 349.1 cm) |
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Answer» Y = 3sin( 36t + 0.018x + π/4) Compare this equation with Y = Asin( wt + Kx + ∅) A = 3 cm w = 36 K = 0.018 ∅ = π/4 Speed of wave (V) = w/K = 36 /0.018 = 2000 cm/s = 20 m/s Frequency ( f) = w/2π = 36/2π = 5.73 Hz Amplitude , A = 3 cm Phase angle ( ∅) = π/4 Wavelength = 2π/K = 2π/0.018 = 348.88 cm = 3.4888 m = 3.49 m Like my answer if you find it useful! |
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