1.

A trupositive ion of element 'X' has six electrons with I = 0 and five electrons with I = 2. (a) Predict the group and period to which 'X' belongs. (b) Dose the element show variable valencies? Justify.

Answer»

Solution :(a) 1 = 0 corresponds to 's' SUBSHELL and 1 = 2
corresponds to 'd' subshell. Further, six electrons
in 's' subshell and five electrons in 'd' subshell
means the ion should have the electronic
configuration `1s^(2)2s^(2)2p^(6)3s^(2)3p^(6)3d^(5)`. Since it is
a tripositive ion, the atom could have lost two
electtrons from 4s subshell and one electron
form 3d subshell. Therefore, atomic number is
26. Electronic configuration is [Ar] `3d^(6)4s^(2)` It
belongs to the VIII group and 4TH period.
(b) Yes. Since Fe is a transition element it shows
variable oxidationn state. In transition ELEMENTS,
the electrons enter into the penultimate shell
instead od calence shell. Energy difference
between ns and `(n -1)d`orditals is very less.
Hence, both ns and `(n -1)d` electrons are available for chemical bond formation. So,
they exhibit veriable valency.


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