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A trupositive ion of element 'X' has six electrons with I = 0 and five electrons with I = 2. (a) Predict the group and period to which 'X' belongs. (b) Dose the element show variable valencies? Justify. |
Answer» Solution :(a) 1 = 0 corresponds to 's' SUBSHELL and 1 = 2 corresponds to 'd' subshell. Further, six electrons in 's' subshell and five electrons in 'd' subshell means the ion should have the electronic configuration `1s^(2)2s^(2)2p^(6)3s^(2)3p^(6)3d^(5)`. Since it is a tripositive ion, the atom could have lost two electtrons from 4s subshell and one electron form 3d subshell. Therefore, atomic number is 26. Electronic configuration is [Ar] `3d^(6)4s^(2)` It belongs to the VIII group and 4TH period. (b) Yes. Since Fe is a transition element it shows variable oxidationn state. In transition ELEMENTS, the electrons enter into the penultimate shell instead od calence shell. Energy difference between ns and `(n -1)d`orditals is very less. Hence, both ns and `(n -1)d` electrons are available for chemical bond formation. So, they exhibit veriable valency. |
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