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A tube open at both ends has length 47 cm. Calculate the fundamental frequency of air column. ( Neglect end correction. Speed of sound in air ` 3.3 xx 10 ^( 2 ) ` m/s ) . |
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Answer» Given : Length of tube (l) = 47 cm = 0.47 m, speed of sound (v) ` = 3.3 xx 10 ^ 2 ` m/s. Fundamental frequency of air column in a tube open at both ends, `n = ( v ) /( 2l ) = ( 3.3 xx 10 ^ 2 )/( 2 xx 0.47 ) = 351. 06 ` Hz |
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