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A tyre pumped to a pressure of `6 atmosphere` bursts suddenly. Calculate the temperature of escaping air. Given initial room temperature is `15^(@)C` and gamma for air is 1.4`. |
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Answer» Correct Answer - `176.2K` `P_(1)= 6 atm. P_(2)= 1 atm` `T_(1)= 273+15= 288K, T_(2)= ? gamma= 1.4` From `P_(2)^((1-gamma))T_(2)^(gamma)= P_(1)^((1-gamma))T_(1)^(gamma)` `T_(2)= T_(1)((P_(1))/(P_(2)))^((1-gamma)//(gamma))=288(6/1)^(((1-1.4))/(1.4))` `=288xx6^(-2//7)= 172.6K` |
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