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A uniform circular disc of mass `M` and radius `R` rolls without slipping on a horizontal surface. If the velocity of its centre is `v_0`, then the total angular momentum of the disc about a fixed point `P` at a height `(3R)//2` above the centre `C`. A. increases continuously as the disc moves awayB. decreases continuously as the disc moves awayC. is equal to `2MRv_(0)`D. is equal to `MRv_(0)` |
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Answer» Correct Answer - D `vecL=I_(CM)vecomega=mvecrxxvecv_(CM)` `=(MR^(2))/2omega(-hatk)+M3/2 R(-hatj)xxv_(0)hati` `=MRv_(0)hatk` |
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